(2x+7)(x^2+2x-3)=0

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Solution for (2x+7)(x^2+2x-3)=0 equation:


Simplifying
(2x + 7)(x2 + 2x + -3) = 0

Reorder the terms:
(7 + 2x)(x2 + 2x + -3) = 0

Reorder the terms:
(7 + 2x)(-3 + 2x + x2) = 0

Multiply (7 + 2x) * (-3 + 2x + x2)
(7(-3 + 2x + x2) + 2x * (-3 + 2x + x2)) = 0
((-3 * 7 + 2x * 7 + x2 * 7) + 2x * (-3 + 2x + x2)) = 0
((-21 + 14x + 7x2) + 2x * (-3 + 2x + x2)) = 0
(-21 + 14x + 7x2 + (-3 * 2x + 2x * 2x + x2 * 2x)) = 0
(-21 + 14x + 7x2 + (-6x + 4x2 + 2x3)) = 0

Reorder the terms:
(-21 + 14x + -6x + 7x2 + 4x2 + 2x3) = 0

Combine like terms: 14x + -6x = 8x
(-21 + 8x + 7x2 + 4x2 + 2x3) = 0

Combine like terms: 7x2 + 4x2 = 11x2
(-21 + 8x + 11x2 + 2x3) = 0

Solving
-21 + 8x + 11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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